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A gaseous mixture containing He,CH_(4) and SO_(2) was allowedwas allowedto effuse through a fine hole then find what molar ratio of gases coming out initially ? If mixture contain He, CH_(4) and SO _(2) in 1:2:3 mole ratio. |
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Answer» `2:2:3` `(n'_(He))/(n'_(SO_(2)))=(1)/(3)sqrt((64)/(3))=(4)/(3)` `n'_(He):n'_(CH_(4)):n'_(SO_(2))=4:4:3` |
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