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A gaseous mixture containing He,CH_(4) and SO_(2) was allowedwas allowedto effuse through a fine hole then find what molar ratio of gases coming out initially ? If mixture contain He, CH_(4) and SO _(2) in 1:2:3 mole ratio.

Answer» <html><body><p>`2:2:3`<br/>`6:6:<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2):sqrt(2):3`<br/>`4:4:3`</p>Solution :`(n'_(He))/(n'_(CH_(4)))=(1)/(2)sqrt((<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>)/(4))=(1)/(1)`<br/> `(n'_(He))/(n'_(SO_(2)))=(1)/(3)sqrt((64)/(3))=(4)/(3)` <br/> `n'_(He):n'_(CH_(4)):n'_(SO_(2))=4:4:3`</body></html>


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