1.

A gaseous mixture containing He,CH_(4) and SO_(2) was allowedwas allowedto effuse through a fine hole then find what molar ratio of gases coming out initially ? If mixture contain He, CH_(4) and SO _(2) in 1:2:3 mole ratio.

Answer»

`2:2:3`
`6:6:1`
`SQRT(2):sqrt(2):3`
`4:4:3`

Solution :`(n'_(He))/(n'_(CH_(4)))=(1)/(2)sqrt((16)/(4))=(1)/(1)`
`(n'_(He))/(n'_(SO_(2)))=(1)/(3)sqrt((64)/(3))=(4)/(3)`
`n'_(He):n'_(CH_(4)):n'_(SO_(2))=4:4:3`


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