A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number fo moles of all the gases is 10. If the partial pressures ofA and B are 3.0 and 1.0 atm respectively and if C has a molecular mass of 2.0, then calculate the weight of C in g present in the mixture.

A gaseous mixture of three gases A, B and C has a pressure of 10 atm.

1.	A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number fo moles of all the gases is 10. If the partial pressures ofA and B are 3.0 and 1.0 atm respectively and if C has a molecular mass of 2.0, then calculate the weight of C in g present in the mixture.
Answer» Solution :`P_(A)=3.0" atm", P_(B)=1.0" atm"` Hence, `"" P_(C )=10-(3+1)=6" atm"` `P_(C )=(n_(C ))/(n_("TOTAL"))xxP_("total")=(W)/(M)xx(1)/(n_("total"))xxP_("total")` `:. "" 6.0=(w)/(2)xx(1)/(10)xx10" or "w=12" g"`