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A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number fo moles of all the gases is 10. If the partial pressures ofA and B are 3.0 and 1.0 atm respectively and if C has a molecular mass of 2.0, then calculate the weight of C in g present in the mixture.

Answer» <html><body><p></p>Solution :`P_(A)=3.0" atm", P_(B)=<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.0" atm"` <br/> Hence, `"" P_(C )=10-(3+1)=<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>" atm"` <br/> `P_(C )=(n_(C ))/(n_("<a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a>"))xxP_("total")=(<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>)/(M)xx(1)/(n_("total"))xxP_("total")` <br/> `:. "" 6.0=(w)/(2)xx(1)/(10)xx10" or "w=12" g"`</body></html>


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