InterviewSolution
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InterviewSolution
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(a)Give reasons for the following : Nitric oxide becomes brown when released in air. (b)Ammonia acts as a ligand. Why ? ( c)Assign a reason for the following: `SCl_(6)` is not known but `SF_(6)` is known. |
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Answer» (a)Nitric oxide has one unpaired electron and hence is very reactive. As a result, it readily combines with `O_(2)` of the air to form nitrogen dioxide `(NO_(2))` which has brown colour. `underset("Colourless")(2NO)+O_(2)tounderset("Brown")(2NO_(2))` (b)Due to the presence of a lone pair of electrons on `N,NH_(3)` acts as a complexing agent (ligand).As a result, it combines with transition metal cations to form complexes.For example : `underset("Silver chloride")(AgCl)+ 2NH_(3) to underset("Diamminesilver(I)chloride")([Ag(NH_(3))_(2)]Cl)` `underset("copper sulphate")(CuSO_(4))+ 4NH_(3) to underset("Tetraamminecopper(II)suplhate")([Cu(NH_(3))_(4)]SO_(4))` `underset("Cromium chloride")(CrCl_(3))+ 6NH_(3) to underset("Hexaammine chromium(III)chloride")([Cr(NH_(3))_(6)]Cl_(3))` (c )Fluorine is a much stronger oxidizing agent than chlorine, therefore, it can easily oxidise sulphur to its maximum oxidation state of `+6` and hence forms `SF_(6)`.Chlorine, on the other hand, being a weaker oxidizing agent can oxidies sulphur at the maximum to its `+4` oxidation state and hence can form `SCl_(4)` but not `SCl_(6)`. |
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