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A given sample of pure compound contains `9.81 g` of Zn, `1.8xx10^(23)` atoms of chromium, and `0.60` mol of oxygen atoms. What is the simplest formula?A. (a)`ZnCr_(2)O_(7)`B. (b)`ZnCr_(2)O_(4)`C. (c )`ZnCrO_(4)`D. (d)`ZnCrO_(6)` |
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Answer» Correct Answer - B Moles of `Zn=9.81/65.39=0.15` Moles of `Cr=(1.8xx10^(23))/(6.023xx10^(23))=0.3` Moles of `O=0.6` So, whole molar ratio `=0.15:0.3:0.6=1:2:4` Hence, formula`=ZnCr_(2)O_(4)` |
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