1.

A given sample of pure compound contains `9.81 g` of Zn, `1.8xx10^(23)` atoms of chromium, and `0.60` mol of oxygen atoms. What is the simplest formula?A. (a)`ZnCr_(2)O_(7)`B. (b)`ZnCr_(2)O_(4)`C. (c )`ZnCrO_(4)`D. (d)`ZnCrO_(6)`

Answer» Correct Answer - B
Moles of `Zn=9.81/65.39=0.15`
Moles of `Cr=(1.8xx10^(23))/(6.023xx10^(23))=0.3`
Moles of `O=0.6`
So, whole molar ratio
`=0.15:0.3:0.6=1:2:4`
Hence, formula`=ZnCr_(2)O_(4)`


Discussion

No Comment Found

Related InterviewSolutions