InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A glass rod of radius `r_(1)` is inserted symmetrically into a vertical capillary tube of radius `r_(2)` such that their lower ends are at the same level. The arrangement is now dipped in water. The height to which water will rise into the tube will be (`sigma =` surface tension of water, `rho = ` density of water)A. `(2sigma)/((r_(2)-r_(1))rhog)`B. `(2sigma)/((r_(2)-r_(1))rhog)`C. `(2sigma)/((r_(2)-r_(1))rhog)`D. `(2sigma)/((r_(2)^(2)+r_(1)^(2))rhog)` |
|
Answer» Correct Answer - A Total upward force dur to surface tension `=sigma(2pir_(1)+2pir_(2))` This supports the weight of the liquid column of height h. Weight of liquid column liquid column of height h. Weight of liquid column `=h=[pir_(2)^(2)+2pir_(2))]rhog` Equating, We get `hpi(r_(2)+r_(1))(r_(2)-r_(1))rhog=2pisigma(r_(1)+r_(2))` or `h(r_(2)-r_(1))rhog=2sigma` or `h=(2sigma)/((r_(2)-r_(1))rhog)` |
|