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A halide of Be(X) sublimes on heating and is a bad conductor of electricity in molten state. From its aqueous solution it is diffucult to obtain anhydrous salt. This halide of berylium (X) is obtained by heating berylium oxide with carbon tetrachloride at 800^(@)C. This halide of berylium forms a complex of the M_(2)[BeX_(4)] What is the compound formed when BeCI_(2) disolves in water in cold conditions ? |
Answer» <html><body><p>`Be(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>BeO<br/>`BeO_(2)`<br/>`[Be(H_(2)O)_(4)]CI_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/complex-926309" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLEX">COMPLEX</a> compound formed in cold <a href="https://interviewquestions.tuteehub.com/tag/condition-409743" style="font-weight:bold;" target="_blank" title="Click to know more about CONDITION">CONDITION</a> is `[Be (H_(2)O)_(4)CI_(2)`</body></html> | |