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A hard water sample contains dissolved Mg(HCO_3)_2only. If degree of hardness of that sample is 150ppm, calculate the weight of Mg(HCO_3)_2present in 1kg of water sample.

Answer» <html><body><p></p>Solution :Degree of hardness is 150ppm. It means that `10^6`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> sample contains 150 g of `CaCO_3`(which is equivalent to `Mg(HCO_3)_2` .<br/>Weight of `CaCO_3`in <a href="https://interviewquestions.tuteehub.com/tag/1kg-282991" style="font-weight:bold;" target="_blank" title="Click to know more about 1KG">1KG</a> `(10^3 g)` of water<br/>`= (10^3 xx 150)/(10^6) =0.15 g ` <br/>0.15 g of `CaCO_3 -= 0.219 g ` of `Mg(HCO_3)_2`<br/>0.15 g of `CaCO_3 -= (146 xx 0.15)/(100)` <br/>`= 0.219g Mg (HCO_3)_2` <br/>Weight of `Mg(HCO_3)_2`present in 1kg of water = 0.219 gram</body></html>


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