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A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iii) angular frequency |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a>, `y=0.5cos(1500pit+0.8)=0.5sin((<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` <br/> `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` <br/> Now (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) angular <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> `omega=1500pi=4.713xx10^(3)" rads"^(-1)`</body></html> | |