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A heated copper block at 130^(@)C loses 340 J ofheat to the surroundings which are at room temperature of 32^(@)C . Calculate (i) the entropy change of the system ( copper block )(ii) the entropy change in the surrounding (iii) the total entropy changein the universe due to this process Assume that the temperature of the block and the surroundings remains constant. |
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Answer» Solution :`T_("system") 130^(@)C = 130 + 273 K = 403 K, T _(surr) = 32^(@)C = 32 + 273 K = 305K` `q_("system") = -340 J , Q _(surr) =+ 340 J` (i) `DeltaS_("system") = (q _("system"))/(T_("system")) = ( -340J)/(403K) = - 0.84JK ^(-1) `(ii) `DeltaS_(surr) = (q_(surr))/(T_(surr))= (+340J)/(350K) = + 1.11 JK^(-1)` (III) `DeltaS_("total")`or `DeltaS_("system") + DeltaS_(surr) = - 0.84 + ( +1.11) JK^(-1)= 0.27 JK^(_1)` |
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