A hemispherical bowl of radius R is set rotating about its axis of symmetry which is kept vertical A small block kept in the bowl rotates with the bowl without slipping on its surface If the surface of bowl is smooth and angle made by radius through the block with the vertical is 0 find the angular speed at which the bowl is rotating .

A hemispherical bowl of radius R is set rotating about its axis of sym

1.	A hemispherical bowl of radius R is set rotating about its axis of symmetry which is kept vertical A small block kept in the bowl rotates with the bowl without slipping on its surface If the surface of bowl is smooth and angle made by radius through the block with the vertical is 0 find the angular speed at which the bowl is rotating .
Answer» <html><body><p></p>Solution :Here ` OA = <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>, <a href="https://interviewquestions.tuteehub.com/tag/angleaoc-1978297" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLEAOC">ANGLEAOC</a> = theta` <br/> Block moves in a horizontal circle with centre`C` and <br/> radius` r = AC = R sin theta` <br/> `:.` In equilibrium `N cos theta = <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>` <br/> and `N sin theta = m <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2) (R sin theta)` <br/> `N = m omega^(2) R` <br/> From(i)`m omega^(2) R cos theta = mg` <br/> ` omega = sqrt((g)/(R cos theta))` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V01_C03_S01_397_S01.png" width="80%"/> .</body></html>