A hexagonal close-packed lattic can be represented by figures (a) and (b) below. If c=asqrt((8)/(3))=1.633a , there is an atom at each corner of the unit cell and another atom which can be located by moving one-third the distance along the diagonal of the rhombus base, starting at the lower left hand corner and moving perpendicularly upward by c/2 . Mg crystallizes in this lattice and has a density of 1.74 g cm^(-3). What is the distance between nearest heighbours?

A hexagonal close-packed lattic can be represented by figures (a) and

1.	A hexagonal close-packed lattic can be represented by figures (a) and (b) below. If c=asqrt((8)/(3))=1.633a , there is an atom at each corner of the unit cell and another atom which can be located by moving one-third the distance along the diagonal of the rhombus base, starting at the lower left hand corner and moving perpendicularly upward by c/2 . Mg crystallizes in this lattice and has a density of 1.74 g cm^(-3). What is the distance between nearest heighbours?
Answer» 1.6 3.2 4.6 8 Solution :DISTANCE between nearest NEIGHBOURS=`3.20overset(@)A` Nearest neighbours are along the BASE edge.