A hexagonal close-packed lattic can be represented by figures (a) and (b) below. If c=asqrt((8)/(3))=1.633a , there is an atom at each corner of the unit cell and another atom which can be located by moving one-third the distance along the diagonal of the rhombus base, starting at the lower left hand corner and moving perpendicularly upward by c/2 . Mg crystallizes in this lattice and has a density of 1.74 g cm^(-3). What is the distance between nearest heighbours?

A hexagonal close-packed lattic can be represented by figures (a) and

1.	A hexagonal close-packed lattic can be represented by figures (a) and (b) below. If c=asqrt((8)/(3))=1.633a , there is an atom at each corner of the unit cell and another atom which can be located by moving one-third the distance along the diagonal of the rhombus base, starting at the lower left hand corner and moving perpendicularly upward by c/2 . Mg crystallizes in this lattice and has a density of 1.74 g cm^(-3). What is the distance between nearest heighbours?
Answer» <html><body><p>1.6<br/>3.2<br/>4.6<br/>8</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between nearest <a href="https://interviewquestions.tuteehub.com/tag/neighbours-1113488" style="font-weight:bold;" target="_blank" title="Click to know more about NEIGHBOURS">NEIGHBOURS</a>=`3.20overset(@)A` Nearest neighbours are along the <a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a> edge.</body></html>