InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A horizontal wire `0*2m` long carries a current of `4A`. Find the magnitude and direction of the magnetic field, which can support the weight of the wire. Given, the mass of the wire is `3xx10^-3kg//m`, `g=10ms^-2`. |
|
Answer» Here, mass of wire, `m=(3xx10^-3)xx0*2kg, I=4A, l=0*2m` In equilibrium position, force `(F=IlB)` on wire carrying current I due to magnetic field is equal to weight (`mg`) of wire, i.e., `IlB=mg` or `B=(mg)/(Il)=((3xx10^-3)xx0*2xx10)/(4xx0*2)` `=7*5xx10^-3T` The weight of wire can be supported by forces F if `vecF` is acting vertically upwards (i.e., opposite to the weight of wire). It will be so if the direction of `vecB` is horizontal and perpendicular to wire carrying current. |
|