1.

(a) How is H_(2)O_(2) prepared?(b) Explain about the structure of H_(2)O_(2).

Answer» <html><body><p></p>Solution :(a) Hydrogen <a href="https://interviewquestions.tuteehub.com/tag/peroxide-1151683" style="font-weight:bold;" target="_blank" title="Click to know more about PEROXIDE">PEROXIDE</a> can be made by adding a metal peroxide to dilute acid. <br/> `BaO_(2(s))+H_(2)SO_(4(aq))toBaSO_(4(aq))+H_(2)O_(2(aq))`<br/>(b) Structure of `H_(2)O_(2)`.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C04_E02_154_S01.png" width="80%"/> <br/>(i) `H_(2)O_(2)`has a non-polar structure. The molecular dimensions in the gas phase and solid phase differ as shown in the figure. <br/>(ii) Both in gas phase and solid phase, the `H_(2)O_(2)`, <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> adopt a skew configuration due to repulsive interaction of the -OH bonds with lone pairs of electrons on each oxygen atom.<br/>(iii) Indeed, it is the smallest molecule known to show hindrance rotation about a single bond. In solid phase, the dihedral angle is <a href="https://interviewquestions.tuteehub.com/tag/sensitive-3019148" style="font-weight:bold;" target="_blank" title="Click to know more about SENSITIVE">SENSITIVE</a> and hydrogen bonding decreasing from `115.5^(@)` in the gas phase to 90.2o, in the solid phase. <br/>(iv) Structurally, `H_2O_2` is represented by the dihydroxyl formula in which the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> O-H groups do not lie in the same plane. In the solid phase of molecule, the dihedral angle reduces to 90.2" due to hydrogen bonding and the `O - O - H` angle expands from `94.8^(@)` to `101.9^(@)`. <br/>(v) One way of explaining the shape of hydrogen peroxide is that the hydrogen atoms would Tie on the pages of a partly opened book, and the oxygen atoms along the spin.</body></html>


Discussion

No Comment Found

Related InterviewSolutions