A hydrocarbon contains 85.7 % C. If 42 mg of the compound contains 3.01xx10^(20)molecules, the molecular formula of the compound will be ......

A hydrocarbon contains 85.7 % C. If 42 mg of the compound contains 3.0

1.	A hydrocarbon contains 85.7 % C. If 42 mg of the compound contains 3.01xx10^(20)molecules, the molecular formula of the compound will be ......
Answer» `C_(3)H_(6)` `C_(6)H_(12)` `C_(12)H_(24)` `C_(2)H_(4)` Solution :Mass of `3.01xx10^(20)` ATOMS `=42xx10^(-3)g` `:.` Mass of `6.02xx10^(23)` atoms `=84g` `:.` Molecular formula : `C_(6)H_(12)` (C of 85.7)