Saved Bookmarks
| 1. |
A hydrocarbon decolourised bromine water. On ozonolysis it gives 3-methyl butanal and acetaldehyde. Write the structure of the hydrocarbon. |
|
Answer» Solution : Since the given hydrocarbon decolourises bromine WATER, it MUST be an unsaturated hydrocarbon. On ozonolysis it gives two aldehydes. Therefore, it must be an alkene. The products of ozonolysis are `UNDERSET("3-methylbutanal")(CH_3 - undersetoverset(|)(CH_3)(C)H - CH_2 - oversetunderset(|)(H)(C)= O)underset("acetaldehyde")(CH_3 - oversetunderset(|)(H)(C) = O)` The STRUCTURE of the given alkene can be obtained by joining the oxygenated carbons of the two aldehydes by a double BOND. Hence, the given hydrocarbon is `underset(5-methylhex-2-ene ")(CH_3- undersetoverset(|)(CH_3)(C)H - CH_2 - oversetunderset(|)(H)(C) = oversetunderset(|)(H)(C)- CH_3` |
|