A hydrocarbon P has molecular formula C_8H_(16), and it does not undergo hydrogenation with raney Ni. A on free radical chlorination yields three monochloro derivatives Q, R and S (all structural isomers) with their molecular formula C_8 H_(15)Cl. Only Q can show optical isomerism R. On further chlorination produces a dichloride C_8 H_(14) Cl_2, as one of the several isomers which on heating with sodium metal in etheral solution gives bicyclo [2, 2, 2] octane. If S is dichlorinated, how many isomers would be produced? (exclude stereoisomers)

A hydrocarbon P has molecular formula C_8H_(16), and it does not under

1.	A hydrocarbon P has molecular formula C_8H_(16), and it does not undergo hydrogenation with raney Ni. A on free radical chlorination yields three monochloro derivatives Q, R and S (all structural isomers) with their molecular formula C_8 H_(15)Cl. Only Q can show optical isomerism R. On further chlorination produces a dichloride C_8 H_(14) Cl_2, as one of the several isomers which on heating with sodium metal in etheral solution gives bicyclo [2, 2, 2] octane. If S is dichlorinated, how many isomers would be produced? (exclude stereoisomers)
Answer» <html><body><p>2<br/>3<br/>5<br/>7</p>Solution :S is <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_034_S01.png" width="80%"/></body></html>