A hydrocarbon 'X' have 81% of carbon. Volume of CO_(2) liberated at 298K and 76 cm of Hg when 0.55gm of 'x' undergoes combustion

A hydrocarbon 'X' have 81% of carbon. Volume of CO_(2) liberated at 29

1.	A hydrocarbon 'X' have 81% of carbon. Volume of CO_(2) liberated at 298K and 76 cm of Hg when 0.55gm of 'x' undergoes combustion
Answer» 0.90l 11.09l 1.89l 1.09l Solution :`100 g ---- RARR 81g` `0.55g --------rarr 0.4455 g` `12g rarr24.4658l (V=(nRT)/(P)=(1xx0.0821xx298)/(1))` `0.4455 g rarr 0.908 l`