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A hydrocarbon (X) was found to have a molecular weight of 80-85. A 10.02 mg sample took up 8.40mL of H_(2) gas measured at 0^(@)C and 760 mm pressure. Ozonolysis of (X) yields only HCHO and OHC-CHO. What was hydrocarbon?

Answer» <html><body><p>`C_(6)H_(8)`<br/>`C_(6)H_(10)`<br/>`C_(6)H_(12)`<br/>`C_(6)H_(14)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` taken up <br/> `= (8.40 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(22.4) = 3.75 xx 10^(-4)` <br/> Moles of compound `=(10.02 xx 10^(-3))/(22.4) = 1.254 xx 10^(-4)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, moles of `H_(2)` taken up by 1 mole of compound `=(3.75 xx 10^(-4))/(1.254 xx 10^(-4)) =3` <br/> Therefore, molecules has three double bonds and it may be hexa-1,3,5-triene.</body></html>


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