A hydrocarbon (X) was found to have a molecular weight of 80-85. A 10.02 mg sample took up 8.40mL of H_(2) gas measured at 0^(@)C and 760 mm pressure. Ozonolysis of (X) yields only HCHO and OHC-CHO. What was hydrocarbon?

A hydrocarbon (X) was found to have a molecular weight of 80-85. A 10.

1.	A hydrocarbon (X) was found to have a molecular weight of 80-85. A 10.02 mg sample took up 8.40mL of H_(2) gas measured at 0^(@)C and 760 mm pressure. Ozonolysis of (X) yields only HCHO and OHC-CHO. What was hydrocarbon?
Answer» `C_(6)H_(8)` `C_(6)H_(10)` `C_(6)H_(12)` `C_(6)H_(14)` Solution :MOLES of `H_(2)` taken up `= (8.40 xx 10^(-3))/(22.4) = 3.75 xx 10^(-4)` Moles of compound `=(10.02 xx 10^(-3))/(22.4) = 1.254 xx 10^(-4)` THUS, moles of `H_(2)` taken up by 1 mole of compound `=(3.75 xx 10^(-4))/(1.254 xx 10^(-4)) =3` Therefore, molecules has three double bonds and it may be hexa-1,3,5-triene.