A hydrogen atom emits a photon of energy 12.1 eV. By how much will the angular momentum of the electron change?

A hydrogen atom emits a photon of energy 12.1 eV. By how much will the

1.	A hydrogen atom emits a photon of energy 12.1 eV. By how much will the angular momentum of the electron change?
Answer» <html><body><p></p>Solution :`E_(n_(2)) - E_(n_(1)) = 12.1 <a href="https://interviewquestions.tuteehub.com/tag/ev-976207" style="font-weight:bold;" target="_blank" title="Click to know more about EV">EV</a> = 13.6 ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` <br/> This equation is correct for transition from `n_(2) = 3 " to " n_(1) = 1` <br/> Angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> `= (<a href="https://interviewquestions.tuteehub.com/tag/nh-570695" style="font-weight:bold;" target="_blank" title="Click to know more about NH">NH</a>)/(2pi)` <br/> `:.` Change in angular momentum `= (h)/(2pi) (n_(2) - n_(1)) = (h)/(2pi) (3 -1) = (h)/(pi) = (6.626 xx 10^(-34)Js)/(3.<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)` <br/> `= 2.11 xx 10^(-14) Js`</body></html>