A hydrogen atom emits a photon of energy 12.1 eV. By how much will the angular momentum of the electron change?

A hydrogen atom emits a photon of energy 12.1 eV. By how much will the

1.	A hydrogen atom emits a photon of energy 12.1 eV. By how much will the angular momentum of the electron change?
Answer» Solution :`E_(n_(2)) - E_(n_(1)) = 12.1 EV = 13.6 ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` This equation is correct for transition from `n_(2) = 3 " to " n_(1) = 1` Angular MOMENTUM `= (NH)/(2pi)` `:.` Change in angular momentum `= (h)/(2pi) (n_(2) - n_(1)) = (h)/(2pi) (3 -1) = (h)/(pi) = (6.626 xx 10^(-34)Js)/(3.14)` `= 2.11 xx 10^(-14) Js`