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A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl or `pH = 10` and by passing bydrogen gas around the platinum wire at one atm pressure . The oxidation potential of electrode would be ?A. 0.059 VB. 0.59 VC. 0.118 VD. 1.18 V |
Answer» Correct Answer - B (b) For hydrogent electrode, oxidation half reaction is `underset((1 atm))(H_(2)) to underset(" (At pH 10)")(2H^(+))+2e^(-)` If pH=10 `H^(+)=1xx10^(-pH)=1xx10^(-10)` From Nernst equation, `E_(cell) =E_(cell)^(@)-(0.0591)/(2)log""([H^(+)]^(2))/(p_(H_(2)))` For hydrogen electrode, `E_(cell)^(@)=0` `E_(cell)-(0.0591)/(2) log""((10^(-10))^(2))/(1)` `=+(0.0591xx1)/(2) log""(1)/(10^(-10))` `=0.0591 log 10^(10)=0.0591xx10=0.591 V` |
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