(a) In a cell reaction, equilibrium constant L is less than one. Is `E^(@)` for the cell positive or negative ? (b) What will be the value of K if `E_(cell)^(@)=0` ?

(a) In a cell reaction, equilibrium constant L is less than one. Is `E

1.	(a) In a cell reaction, equilibrium constant L is less than one. Is `E^(@)` for the cell positive or negative ? (b) What will be the value of K if `E_(cell)^(@)=0` ?
Answer» (a) For a cell , `E^(@)=(0.0591)/(n)logK` Let the value of K be 0.01 (less than one) `E^(@)=(0.0591)/(n)log0.01=(0.0591)/(n)log(10^(-2))=(-(2)xx(0.0591))/(n)=-"ve"`. (b) If `E_(cell)^(@)=0, "then" 0=(0.0591)/(n)log K" or " log K=0,K="Antilog"(0)=1`.

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(a) In a cell reaction, equilibrium constant L is less than one. Is `E^(@)` for the cell positive or negative ? (b) What will be the value of K if `E_(cell)^(@)=0` ?

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