A large tank is filled with water to a height `H`. A small hole is made at the base of the tank. It takes `T_(1)` time to decrease the height of water to `(H)/(eta) (eta gt 1)`, and it takes `T_(2)` times to take out the rest of water. If `T_(1) = T_(2)`, then the value of `eta` isA. 2B. 3C. 4D. `2sqrt(2)`

A large tank is filled with water to a height `H`. A small hole is mad

1.	A large tank is filled with water to a height `H`. A small hole is made at the base of the tank. It takes `T_(1)` time to decrease the height of water to `(H)/(eta) (eta gt 1)`, and it takes `T_(2)` times to take out the rest of water. If `T_(1) = T_(2)`, then the value of `eta` isA. 2B. 3C. 4D. `2sqrt(2)`
Answer» Correct Answer - C Apply result from Q. 16 of Ex-II `t=(A)/(A_(0))sqrt((2)/(g))lfloor(sqrt(H)-sqrt(x))rfloorimpliesT_(1)=(A)/(A_(0))sqrt((2)/(g))lfloor(sqrt(H)-sqrt(H//eta))rfloor" "…(1)` `T_(2)=(A)/(A_(0))sqrt((2)/(g))lfloorsqrt(H//eta)-sqrt(0)rfloor" "...(2)` From (1) and (2) `eta=4`

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A large tank is filled with water to a height `H`. A small hole is made at the base of the tank. It takes `T_(1)` time to decrease the height of water to `(H)/(eta) (eta gt 1)`, and it takes `T_(2)` times to take out the rest of water. If `T_(1) = T_(2)`, then the value of `eta` isA. 2B. 3C. 4D. `2 sqrt(2)`
A large tank is filled with water to a height `H`. A small hole is made at the base of the tank. It takes `T_(1)` time to decrease the height of water to `(H)/(eta) (eta gt 1)`, and it takes `T_(2)` times to take out the rest of water. If `T_(1) = T_(2)`, then the value of `eta` isA. `2`B. `3`C. `4`D. `2sqrt(2)`

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