A light ray is incident on a horizontal plane mirror at an angle of `45^(@)`. At what angle should a second plane mirror be placed in order that the refelcted ray finally be reflected horizontally form the second mirror, as shown in figure A. `theta=30^(@)`B. `theta=24^(@)`C. `theta=22.5^(@)`D. `theta=67.5^(@)`

A light ray is incident on a horizontal plane mirror at an angle of `4

1.	A light ray is incident on a horizontal plane mirror at an angle of `45^(@)`. At what angle should a second plane mirror be placed in order that the refelcted ray finally be reflected horizontally form the second mirror, as shown in figure A. `theta=30^(@)`B. `theta=24^(@)`C. `theta=22.5^(@)`D. `theta=67.5^(@)`
Answer» (c) From figure `CD=` emergent ray and `CD` is parallel to `PQ` and `BC` is a line intersecting these parallel lines, So, `/_DCB/_CBQ=180^(@)` `/_DCN+/_NCB+/_CBQ=180^(@)` `alpha+alpha+45^(@)=180^(@)` `alpha=67.5^(@)` But `/_NCS=90^(@)` So, second mirror is at an angle of `22.5^(@)` with horizontal .

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