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A light rod of length 200cm is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross-section 0.1cm^(2) and the other of brass of cross-section 0.2 cm^(2). A distance long the rod at which a weight may be hung to produce equal stresses in both the wires?

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(3)` m from steel <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a><br/>`(4)/(3)` m from brass wire<br/>1m from steel wire<br/>`(1)/(4)` m from brass wire</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MTG_NEET_GID_PHY_XI_C07_E01_004_S01.png" width="80%"/> <br/> As stresses are equal, so `(T_(1))/(A_(1)) = (T_(2))/(A_(2))`<br/> or `(T_(1))/(T_(2)) = (A_(1))/(A_(2)) = (0.1)/(0.2) or T_(2) = 2T_(1)` <br/> Now for <a href="https://interviewquestions.tuteehub.com/tag/translatory-3229314" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATORY">TRANSLATORY</a> equilibrium of the rod, <br/> `T_(1) + T_(2) = W` <br/> From (i) and (ii), we get `T_(1)= (W)/(3), T_(2) = (2W)/(3)` <br/> Now, if <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> is the distance of weight W from steel wire, then for rotational equilibrium of rod, `T_(1) x = T_(2) (2-x) or (W)/(3) x = (2W)/(3) (2-x) :. x= (4)/(3)m`</body></html>


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