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A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. What happens when equilibrium is restored finally and what will be the final vapour pressure ?

Answer» <html><body><p></p>Solution :`underset("Low pressure")(A_((l)))tounderset("<a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> pressure")(A_((g))` <br/> If volume is increased at constant temperature, pressure decreases, since, `p prop 1//V` at constant temperature. <br/> When <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> is <a href="https://interviewquestions.tuteehub.com/tag/restored-7708965" style="font-weight:bold;" target="_blank" title="Click to know more about RESTORED">RESTORED</a> finally the rate of <a href="https://interviewquestions.tuteehub.com/tag/evaporation-16312" style="font-weight:bold;" target="_blank" title="Click to know more about EVAPORATION">EVAPORATION</a> again becomes equal to the rate of condensation and the final vapour pressure becomes equal to the vapour pressure that was before the sudden <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> in the volume of the container.</body></html>


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