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A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. (a) What is the initial effect of the change on vapour pressure ? (b) How do rates of evaporation and condensation change initially? (c) What happens when equilibrium is restored finally and what will be the final vapour pressure ?

Answer» <html><body><p></p>Solution :(a) Initially the vapour pressure will increase. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) The rate of evaporation will remain constant at constant temperature in closed vessel. <a href="https://interviewquestions.tuteehub.com/tag/however-1032379" style="font-weight:bold;" target="_blank" title="Click to know more about HOWEVER">HOWEVER</a>, rate of <a href="https://interviewquestions.tuteehub.com/tag/condensation-19217" style="font-weight:bold;" target="_blank" title="Click to know more about CONDENSATION">CONDENSATION</a> will be low initially, because there are lesser number of molecules per <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> volume in the vapour <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a>. Therefore, the number of collisions per unit volume with the liquid surface decreases. <br/> (c) When equilibrium is restored, rate of evaporation becomes equal to rate of condensation. The final vapour pressure will be same as it was originally.</body></html>


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