A man generates a symmetrical pulse in a string by moving his hand up and down. At t = 0, the point in his hand moves downwards from mean position. The pulse travels with speed `3m//s` on the string and his hand passes 6 times in each second from the mean position. Then, the point on the string at a distance 3 m will reach its upper extreme first time at t =A. 1.25 secB. 1 secC. `13/12` secD. none

A man generates a symmetrical pulse in a string by moving his hand up

1.	A man generates a symmetrical pulse in a string by moving his hand up and down. At t = 0, the point in his hand moves downwards from mean position. The pulse travels with speed `3m//s` on the string and his hand passes 6 times in each second from the mean position. Then, the point on the string at a distance 3 m will reach its upper extreme first time at t =A. 1.25 secB. 1 secC. `13/12` secD. none
Answer» Correct Answer - A or C or D `f=3 Hz " " rArr T=1/3 sec` `lambda=1m` His hand at upper extreme at `(3T)/4=1/4` sec This message reaches x=3 at t=1 sec. later. `rArr 1.25 sec`

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