A mass `m_(1)` moves with a great velocity. It strikes another mass `m_(2)` at rest in head-on collision. It comes back along its path with low speed after collision. ThenA. `m_(1)gtm_(2)`B. `m_(1)ltm_(2)`C. `m_(1)=m_(2)`D. there is no relation between `m_(1)` and `m_(2)`

A mass `m_(1)` moves with a great velocity. It strikes another mass `m

1.	A mass `m_(1)` moves with a great velocity. It strikes another mass `m_(2)` at rest in head-on collision. It comes back along its path with low speed after collision. ThenA. `m_(1)gtm_(2)`B. `m_(1)ltm_(2)`C. `m_(1)=m_(2)`D. there is no relation between `m_(1)` and `m_(2)`
Answer» Correct Answer - B Conservation of linear rmomentum just before and after yields. ltbr `m_(1)vi=m_(2)v_(2)i+m_(1)v_(1)(-i)`…..i `implies m_(1)v=m_(2)v_(2)-m_(1)v_(1)` `e=-(v_(1)+v_(2))/(0-v)=1` therefore `v=v_(1)+v_(2)` ………ii [for elastic collision `e=1`] Elaminating `v_(2)` form i and ii we obtain `m_(1)v=m_(2)(v-v_(1))-m_(1)v_(1)` `implies v_(1)=(m_(2)-m_(1))/(m_(1)=m_(2))v` Since `v_(1)gt0,(m_(2)-m_(1))/(m_(1)+m_(2))gt1` `impliesm_(2)-m_(1)gt0impliesm_(1)ltm_(2)`.

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A mass `m_(1)` moves with a great velocity. It strikes another mass `m_(2)` at rest in head-on collision. It comes back along its path with low speed after collision. ThenA. `m_(1)gtm_(2)`B. `m_(1)ltm_(2)`C. `m_(1)=m_(2)`D. there is no relation between `m_(1)` and `m_(2)`

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