1.

A metal (atomic mass = 50)has a body centred cubic crystal structure.The density of the metal is5.96 " g cm"^(-3) 1 find the volume of the unit cell = ( N_(0)= 6.023 xx 10^(23)atoms"mol"^(-1) )

Answer»


SOLUTION :Mass of the unit cell = Mass of one ATOM ` xx ` No. of atoms present in the unit cell.
`= ((50)/(6.023xx10^(23))G)xx2 [ For BCC, Z =2] `
Volume of the unit cell = `("mass")/("Density")= ( 50xx2)/(6.023 xx 10^(23)) g xx 1/((5.96 " g CM"^(-3)) = 2.786 xx 10^(-23)" cm" ^(3)`


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