Saved Bookmarks
| 1. |
A metal (atomic mass = 50)has a body centred cubic crystal structure.The density of the metal is5.96 " g cm"^(-3) 1 find the volume of the unit cell = ( N_(0)= 6.023 xx 10^(23)atoms"mol"^(-1) ) |
|
Answer» `= ((50)/(6.023xx10^(23))G)xx2 [ For BCC, Z =2] ` Volume of the unit cell = `("mass")/("Density")= ( 50xx2)/(6.023 xx 10^(23)) g xx 1/((5.96 " g CM"^(-3)) = 2.786 xx 10^(-23)" cm" ^(3)` |
|