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A metal (atomic mass = 50)has a body centred cubic crystal structure.The density of the metal is5.96 " g cm"^(-3) 1 find the volume of the unit cell = ( N_(0)= 6.023 xx 10^(23)atoms"mol"^(-1) ) |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the unit cell = Mass of one <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> ` xx ` No. of atoms present in the unit cell.<br/> `= ((50)/(6.023xx10^(23))<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)xx2 [ For <a href="https://interviewquestions.tuteehub.com/tag/bcc-389643" style="font-weight:bold;" target="_blank" title="Click to know more about BCC">BCC</a>, Z =2] ` <br/>Volume of the unit cell = `("mass")/("Density")= ( 50xx2)/(6.023 xx 10^(23)) g xx 1/((5.96 " g <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>"^(-3)) = 2.786 xx 10^(-23)" cm" ^(3)`</body></html> | |