A metal has a fcc lattice. The edge length of the unit cell is 404 pm.The density of the metal is 2.72 "g cm"^(-3). The molar mass of the metal is (N_A , Avogadro's constant =6.02xx10^23 "mol"^(-1))

A metal has a fcc lattice. The edge length of the unit cell is 404 pm.

1.	A metal has a fcc lattice. The edge length of the unit cell is 404 pm.The density of the metal is 2.72 "g cm"^(-3). The molar mass of the metal is (N_A , Avogadro's constant =6.02xx10^23 "mol"^(-1))
Answer» <html><body><p>`"40 g mol"^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`"30 g mol"^(-1)`<br/>`"27 g mol"^(-1)`<br/>`"<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> g mol"^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Density , `rho=(ZxxM)/(a^3xxN_Axx10^(-30))` <br/> `therefore 2.72=(4xxM)/((404)^3xx(6.02xx10^23)xx10^(-30))` or `M=(2.72xx(404)^3xx6.02xx10^23xx10^(-30))/4`<br/> `=27 "g mol"^(-1)`</body></html>