A metal is known to form fluoride `MF_(2)`. When `10` ampere electricity is passed through a molten salt for `330` sec, `1.95 g` metal is deposited. Find out the atomic weight of metal. What will be the quantity of charge required to deposit the same mass of `Cu` from `CuSO_(4)(aq.)`? (`At. wt.` of `Cu = 63.6`)A. 57.02B. 148C. 228D. 114

A metal is known to form fluoride `MF_(2)`. When `10` ampere electrici

1.	A metal is known to form fluoride `MF_(2)`. When `10` ampere electricity is passed through a molten salt for `330` sec, `1.95 g` metal is deposited. Find out the atomic weight of metal. What will be the quantity of charge required to deposit the same mass of `Cu` from `CuSO_(4)(aq.)`? (`At. wt.` of `Cu = 63.6`)A. 57.02B. 148C. 228D. 114
Answer» Correct Answer - D i=10 amp , t = 330 sec , w = 1.95 gm , E = ? `W = (ixxt xx E)/(96500)` `therefore E = (W xx 96500)/(ixxt) = (1.95 xx 96500)/(10 xx 330) = 57.02` Molten salt is `MF_(2)` Valency of fluorine = `(-1) xx 2 = -2` `therefore` Valency of M= + 2 `E = ("At. mass")/("valency")` `therefore` At. mass = `E xx` valency `= 57.02 xx 2 = 114.04 = 114`

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