1.

A metal 'M' having atomic mass 31.25 crystallizes in cubic close packing and it shows "Schottky defects". If the edge length of the cubic lattice is 500 pm and density of the metal is 1.6075 gm//ml then calculate number of moles of metal atom 'M' missing per litre of the crystal. Given : 1 amu = 1.67xx10^(-24)gm

Answer»


SOLUTION : `rho_("ideal")=(ZXX(M_(0))/(N_(A)))/(a^(3))`
`(4xx(31.25)/(N_(A)))/((500xx10^(-10))^(3))=(4xx31.25xx1.67xx10^(-24))/(124xx10^(-24))=1.67g//ml`
`rho_("actual")=1.6075g//ml`
Difference DUE to SCHOTTKEY effect `= 1.67-1.6075rArr0.0625g//ml`
`=0.0625xx10^(3)g//L`
`=62.5 g//L`
`=(62.5)/(31.25)` Mole/L
`=2 "mole"//L`


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