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A metal M reacts with sodium hydroxide to give a white precipitate X which is soluble in excess of NaOH to give Y. Compound X is soluble in HCI to form a compound Z. Identify M.X,Y and Z M , X , Y, Z

Answer» <html><body><p>`Si, SiO_(2),Na_(2)siO_(3),SiCI_(4)`<br/>`AI, AiI(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(3),NaMgO_(3),AICI_(3)`<br/>`Mg,Mg(Oh)_(3),NaMgO_(3),MgCI_(2)`<br/>`Ca,Ca(OH)_(2) ,Na_(2) CO_(3),NaHCO_(3)`</p>Solution :`underset((M))(2AI) + 2NaOH + 6H_(2)O to underset((X))(2AI(OH)_(3)) underset(NaOH)overset("Excess of")(to) underset((Y))(NaAIO_(2))` <br/> `underset((X))(2AI(OH)_(3)) 6HCI to underset((Z))(2AICI_(3)) + 6H_(2) O`</body></html>


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