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A metal M readily forms water soluble MSO_(4) water insoluble M(OH)_(2) and oxide MO which becomes inert on heating. The hydroxide is soluble in NaOH. Then M is: |
Answer» <html><body><p>`Be` <br/>`Mg`<br/>`Ca` <br/>`Sr`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given, `M` reacts to give `MSO_(4)`, which is water <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a>. `M` reacts to give `M (OH)_(2)`, which is water insoluble. `M` reacts to give `MO`, which becomes inert on heating. `M(OH)_(2)` is soluble in `NaOH`, this indicates that `M` is `Be`, since only `Be`, due to its small size and <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> ionisation enthalpy, is amphoteric and <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> `M(OH)_(2)` which dissolves in `NaOH`. <br/> `Be(OH)_(2)+2NaOHrarrNa_(2)BeO_(2)+2H_(2)O` <br/> other facts given are true for `Be` and not for others.</body></html> | |