A metal of density `7.5 xx 10^(3) kg m^(-3)` has an fcc crystal structure with lattice parameter `a = 400 pm`. Calculater the number of unit cells present in `0.015 kg` of metal.A. `6.250 xx 10^(22)`B. `3.125 xx 10^(23)`C. `3.125 xx 10^(22)`D. `1.563 xx 10^(22)`

A metal of density `7.5 xx 10^(3) kg m^(-3)` has an fcc crystal struct

1.	A metal of density `7.5 xx 10^(3) kg m^(-3)` has an fcc crystal structure with lattice parameter `a = 400 pm`. Calculater the number of unit cells present in `0.015 kg` of metal.A. `6.250 xx 10^(22)`B. `3.125 xx 10^(23)`C. `3.125 xx 10^(22)`D. `1.563 xx 10^(22)`
Answer» Correct Answer - C The volume availagble `= (0.015)/(7.5 xx 10^(3))` `("Number of unit cells") xx (400 xx 10^(-12))^(3) = (0.015)/(7.5 xx 10^(3))` `rArr` Number of unit cell `= 3.125 xx 10^(22)`

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A metal of density `7.5 xx 10^(3) kg m^(-3)` has an fcc crystal structure with lattice parameter `a = 400 pm`. Calculater the number of unit cells present in `0.015 kg` of metal.A. `6.250 xx 10^(22)`B. `3.125 xx 10^(23)`C. `3.125 xx 10^(22)`D. `1.563 xx 10^(22)`

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