A metal oxide has the fomula M_2O_3. It can be reduced by hydrogen to give free metal and water. 0.16g of the metal requires 6mg of H_2for complete reduction. The atomic mass of the metal is .n? times the atomic number of calcium. The value of .n. is

A metal oxide has the fomula M_2O_3. It can be reduced by hydrogen to

1.	A metal oxide has the fomula M_2O_3. It can be reduced by hydrogen to give free metal and water. 0.16g of the metal requires 6mg of H_2for complete reduction. The atomic mass of the metal is .n? times the atomic number of calcium. The value of .n. is
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M_(2) O_3 +3H_(2(g)) rarr 2M +3H_2O` <br/> 6g gives`H_2`2 moles of metal <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/6xx10-1913073" style="font-weight:bold;" target="_blank" title="Click to know more about 6XX10">6XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` gm of `H_2`<a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> 0.002 moles of .M. <br/> `0.002 = (0.16)/("M.Wt")` <br/> `:.` M.Wt `=(0.16)/(0.002)=80`</body></html>