A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is

A metal oxide has the formula X_(2)O_(3). It can be reduced by hydroge

1.	A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is
Answer» `15.58` `155.8` `5.58` `55.8` Solution :`X_(2)O_(3)+3H_(2)rarr2X+3H_(2)O` 1 MOLE `rarr 3xx2gm` `?rarr6mg` = 1m boles = `("wt.")/("M.wt.")=(0.1596)/("M.wt")` implies M.wt. = 159.6 `2x+48=159.6impliesx=55.8`