A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is

A metal oxide has the formula X_(2)O_(3). It can be reduced by hydroge

1.	A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is
Answer» <html><body><p>`15.58`<br/>`155.8`<br/>`5.58`<br/>`55.8`</p>Solution :`X_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(3)+3H_(2)rarr2X+3H_(2)O` <br/> <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> `rarr 3xx2gm` <br/> `?rarr6mg` <br/> = 1m boles = `("wt.")/("M.wt.")=(0.1596)/("M.wt")` <br/> implies M.wt. = 159.6 <br/> `2x+48=159.6impliesx=55.8`</body></html>