A metallic element exists as a cubic lattice. Each edge of the unit cell is2.88 Å .The density of the metal is 7.20 g cm^(-3). How many unit cells there will be in 100g of the metal?

A metallic element exists as a cubic lattice. Each edge of the unit ce

1.	A metallic element exists as a cubic lattice. Each edge of the unit cell is2.88 Å .The density of the metal is 7.20 g cm^(-3). How many unit cells there will be in 100g of the metal?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of unit cell = `(2.88 Å )^(3) = 23.9 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>) cm^(3)` <br/> Volume of 100 g of the <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> = `(m)/(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)` <br/> `= 100= 13.9 cm^(3)` <br/> Number of unit cells in this volume = `(139 cm^(3))/(23.9 xx 10^(-24) cm^(3)) = 5.82 xx 10^(23)`</body></html>