1.

A metallic element exists as a cubic lattice. Each edge of the unit cell is2.88 Å .The density of the metal is 7.20 g cm^(-3). How many unit cells there will be in 100g of the metal?

Answer»

Solution :VOLUME of unit cell = `(2.88 Å )^(3) = 23.9 xx 10^(-24) cm^(3)`
Volume of 100 g of the METAL = `(m)/(RHO)`
`= 100= 13.9 cm^(3)`
Number of unit cells in this volume = `(139 cm^(3))/(23.9 xx 10^(-24) cm^(3)) = 5.82 xx 10^(23)`


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