A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is

A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and

1.	A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is
Answer» <html><body><p>30<br/>32<br/>34<br/>42</p>Solution :E.C. of `M^(2+) = 2, 8, <a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>` i.e., it has 24 electrons. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> atom M <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> have electrons = 26 <br/> Hence, protons = 26, <a href="https://interviewquestions.tuteehub.com/tag/neutrons-1114464" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRONS">NEUTRONS</a> `= A - Z = 56 - 26 = 30`</body></html>