A metre scale of mass 100 gm is suspended freely at its end. It is pulled aside and swung about a horizontal axis with an angular velocity 5 rad/s. Calculate the height to which the centre of mass of the scale rises above its lowest position, assuming that there is no friction and air resistance. (given : length of meter scale used = 1m )

A metre scale of mass 100 gm is suspended freely at its end. It is pul

1.	A metre scale of mass 100 gm is suspended freely at its end. It is pulled aside and swung about a horizontal axis with an angular velocity 5 rad/s. Calculate the height to which the centre of mass of the scale rises above its lowest position, assuming that there is no friction and air resistance. (given : length of meter scale used = 1m )
Answer» <html><body><p></p>Solution :`(1//2) Iomega^(2) =mgh, I=(1//3) ml^(2), h = <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(2)<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2), h = l^(2)omega^(2)//<a href="https://interviewquestions.tuteehub.com/tag/6g-331964" style="font-weight:bold;" target="_blank" title="Click to know more about 6G">6G</a> = 1^(2) xx 5^(2)//<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 9.8=0.425 m`</body></html>