1.

A metre scale of mass 100 gm is suspended freely at its end. It is pulled aside and swung about a horizontal axis with an angular velocity 5 rad/s. Calculate the height to which the centre of mass of the scale rises above its lowest position, assuming that there is no friction and air resistance. (given : length of meter scale used = 1m )

Answer»

Solution :`(1//2) Iomega^(2) =mgh, I=(1//3) ml^(2), h = L^(2)OMEGA^(2), h = l^(2)omega^(2)//6G = 1^(2) xx 5^(2)//6 xx 9.8=0.425 m`


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