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A microscope using suitable photons is employed to located an electron in an atom within a distance of 0.1 Å. What is the uncertainty involved in the measurement of its velocity? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, we are given: `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> x = 0.1 Å = 0.1 xx 10^(-10) m = 10^(-11) m` <br/> `h = <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.626 xx 10^(-34) kg m^(2) s^(-1), m = 9.11 xx 10^(-31) kg` <br/> Applying uncertainty principle, `Delta x. (m Delta v) = (h)/(4pi)` <br/> i.e., `Delta v = (h)/(4pi xx m xx Delta x) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> xx 3.14 xx 9.11 xx 10^(-31) kg xx 10^(-11) m) = 5.79 xx 10^(6) ms^(-1)`</body></html> | |