A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 13.2% by weight. 2.58g of the mineral on heating lost 1.232g of CO_(2). Calculate the % by weight of the other metal.

A mineral consists of an equimolar mixture of the carbonates of two bi

1.	A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 13.2% by weight. 2.58g of the mineral on heating lost 1.232g of CO_(2). Calculate the % by weight of the other metal.
Answer» SOLUTION :`M_(1)CO_(3)+M_(2)CO_(3),` mol `wt` of `M_(1)=X,M_(2)` `{:("moles"," "n,n,),(,M_(1)CO_(3),rarrM_(1)O+CO_(2),),(,""n,""n,),(,M_(2)CO_(3),rarrM_(2)O+CO_(2),),(,""n,""n,):}` `88n=1.232impliesn=0.014` `(0.014)(60+x)+0.014(60+y)=2.58` `x+y=64.285""...(i)` `(0.014xx x)/(2.58)=(13.2)/(100)` `x=24.32, y~=40` `%M_(2)=(0.014xx40)/(2.58)xx100=21.7`