A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 13.2% by weight. 2.58g of the mineral on heating lost 1.232g of CO_(2). Calculate the % by weight of the other metal.

A mineral consists of an equimolar mixture of the carbonates of two bi

1.	A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 13.2% by weight. 2.58g of the mineral on heating lost 1.232g of CO_(2). Calculate the % by weight of the other metal.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)CO_(3)+M_(2)CO_(3),` mol `wt` of `M_(1)=<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>,M_(2)` <br/> `{:("moles"," "n,n,),(,M_(1)CO_(3),rarrM_(1)O+CO_(2),),(,""n,""n,),(,M_(2)CO_(3),rarrM_(2)O+CO_(2),),(,""n,""n,):}` <br/> `88n=1.232impliesn=0.014`<br/> `(0.014)(60+x)+0.014(60+y)=2.58`<br/> `x+y=64.285""...(i)`<br/> `(0.014xx x)/(2.58)=(13.2)/(100)` <br/> `x=24.32, y~=40`<br/> `%M_(2)=(0.014xx40)/(2.58)xx100=21.7`</body></html>