1.

A mineral haematite (Fe_(2)O_(3)) contains unwanted material called gangue in addition to Fe_(2)O_(3). If 5 kg of the ore contains 2.78 kg of iron, what is the percentage purity of Fe_(2)O_(3) ?

Answer» <html><body><p><br/></p>Solution :Step I. Mass of pure `Fe_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` in haematite <br/> `underset(bar(112+48(=<a href="https://interviewquestions.tuteehub.com/tag/160g-1794798" style="font-weight:bold;" target="_blank" title="Click to know more about 160G">160G</a>)""2xx56=(<a href="https://interviewquestions.tuteehub.com/tag/112g-1777508" style="font-weight:bold;" target="_blank" title="Click to know more about 112G">112G</a>)))(Fe_(2)O_(3)=2Fe)` <br/> 112 g of iron are present in `Fe_(2)O_(3) = 160 g` <br/> 2.78 kg (2780 g) of iron are present in `Fe_(2)O_(3)=(160)/(11)xx2780=3971.4g=3.9714g`<br/> Step <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>. Percentage purity of haematite mineral <br/> `= ("Mass of "Fe_(2)O_(3))/("Mass of mineral")=(3.9714)/(5.0)xx100=79.43%`.</body></html>


Discussion

No Comment Found