A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4). Total pressure of mixture is 740 mm. What is the partial pressure of nitrogen in mm?

A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4).

1.	A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4). Total pressure of mixture is 740 mm. What is the partial pressure of nitrogen in mm?
Answer» <P>185 MM 370 mm 555 mm 740 mm Solution :`X_(N_2) = ((2//28))/((16/32) + (28/28) + (8/16)) = 1/2`. `implies P_(N_2) = X_(N_2) xx 740 = 1/2 xx 740 = 370 mm`.