A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4). Total pressure of mixture is 740 mm. What is the partial pressure of nitrogen in mm?

A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4).

1.	A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4). Total pressure of mixture is 740 mm. What is the partial pressure of nitrogen in mm?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>185 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/370-1860129" style="font-weight:bold;" target="_blank" title="Click to know more about 370">370</a> mm <br/><a href="https://interviewquestions.tuteehub.com/tag/555-325484" style="font-weight:bold;" target="_blank" title="Click to know more about 555">555</a> mm <br/><a href="https://interviewquestions.tuteehub.com/tag/740-334871" style="font-weight:bold;" target="_blank" title="Click to know more about 740">740</a> mm <br/></p>Solution :`X_(N_2) = ((2//28))/((16/32) + (28/28) + (8/16)) = 1/2`. <br/> `implies P_(N_2) = X_(N_2) xx 740 = 1/2 xx 740 = 370 mm`.</body></html>