A mixture contains 23 g of ethanol and 36 g of water, some acetic acid is added to the mixture and its mole fraction becomes 0.5, how much acetic acid was added?(a) 25 g(b) 75 g(c) 100 g(d) 150 gThe question was asked during an online exam.This intriguing question originated from Mole Fraction and Mass(Weight) Fraction topic in division Moles, Density & Concentration of Basic Chemical Engineering

A mixture contains 23 g of ethanol and 36 g of water, some acetic acid

1.	A mixture contains 23 g of ethanol and 36 g of water, some acetic acid is added to the mixture and its mole fraction becomes 0.5, how much acetic acid was added?(a) 25 g(b) 75 g(c) 100 g(d) 150 gThe question was asked during an online exam.This intriguing question originated from Mole Fraction and Mass(Weight) Fraction topic in division Moles, Density & Concentration of Basic Chemical Engineering
Answer» RIGHT answer is (d) 150 g To explain I WOULD say: Let m grams of acetic ACID was added, => 0.5 = (m/60)/{(23/46) + (36/18) + (m/60)}, => m = 150 g.

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