A mixture in which the mole ratio H_(2) and O_(2)is 2: 1 is used to prepare water by the reaction 2 H_(2) (g) + O_(2) (g) to 2 H_(2)O (g) The total pressure of the container is 0*8 " atm " 20^(@) Cbefore the reaction. Determine the final pressure at 120^(@) C after reaction assuming 80% yield of water.

A mixture in which the mole ratio H_(2) and O_(2)is 2: 1 is used to pr

1.	A mixture in which the mole ratio H_(2) and O_(2)is 2: 1 is used to prepare water by the reaction 2 H_(2) (g) + O_(2) (g) to 2 H_(2)O (g) The total pressure of the container is 0*8 " atm " 20^(@) Cbefore the reaction. Determine the final pressure at 120^(@) C after reaction assuming 80% yield of water.
Answer» SOLUTION :` {:(,2H_(2)(g),+,O_(2)(g),to,2H_(2)O(g)),(" Intial moles" ,2a ,,a,,0):}` As pressureare in the ratio of their moles ` :. 2 a + a = 08 "ATM" or 3 a = 08 or a = (08)/3 "atm " ` THEORETICALLY expected yield of `H_(2)O = 2 a` Actual yield ` 2 a xx 90/100 = 16 a` ` :. H_(2) reacted = 16 a " moles ",O_(2) "reacted "= 0 8 a " moles "` Moles after reaction : ` H_(2)= 2 a - 16 a = 0 4 a, O_(2)= a - 08 a = 02 a ` Total no. of moles ` = 04 a + 02 + 16 a = 22a ` HENCE, FINAL pressure` = 22 xx(08)/3= 0* 59 "atm"`