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A mixture in which the mole ratio H_(2) and O_(2)is 2: 1 is used to prepare water by the reaction 2 H_(2) (g) + O_(2) (g) to 2 H_(2)O (g) The total pressure of the container is 0*8 " atm " 20^(@) Cbefore the reaction. Determine the final pressure at 120^(@) C after reaction assuming 80% yield of water.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` {:(,2H_(2)(g),+,O_(2)(g),to,2H_(2)O(g)),(" Intial moles" ,2a ,,a,,0):}` <br/> As pressureare in the ratio of their moles <br/> ` :. 2 a + a = 0*8 "<a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>" or 3 a = 0*8 or a = (0*8)/3 "atm " `<br/> <a href="https://interviewquestions.tuteehub.com/tag/theoretically-3201659" style="font-weight:bold;" target="_blank" title="Click to know more about THEORETICALLY">THEORETICALLY</a> expected yield of `H_(2)O = 2 a` <br/> Actual yield ` 2 a xx 90/100 = 1*6 a` <br/> ` :. H_(2) reacted = 1*6 a " moles ",O_(2) "reacted "= 0* 8 a " moles "`<br/> Moles after reaction : ` H_(2)= 2 a - 1*6 a = 0* 4 a, O_(2)= a - 0*8 a = 0*2 a `<br/> Total no. of moles ` = 0*4 a + 0*2 + 1*6 a = 2*2a `<br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> pressure` = 2*2 xx(0*8)/3= 0* 59 "atm"`</body></html>


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