A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H_2SO_4 . The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with c

1.	A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H_2SO_4 . The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
Answer» 4.4 1.4 2.8 3 Solution :2.3 gm formic ACID (HCOOH) ` = (2.3)/(46) = 1/20 ` mol HCOOH 4.5 gram oxalic acid `(H_2 C_2O_4) ` = (4.5)/(90) = 1/20 ` mol `H_2C_2O_4` (i) `UNDERSET(1/20 "mol")(HCOOH) overset(CONC. H_2SO_4)(to) underset(1/20 "mol")(CO + H_2O)` (ii) `H_2C_2 O_4 overset(conc. H_2SO_4)(to) CO + CO_2 + H_2O` `CO_2`will be absorbed in KOH anc CO isadditional product. Total MOLES of additional `CO_2 = 1/20 + 1/20 = 1/10`mol ` = 1/10 "mol" = 1/10 xx 28 = 2.8 g`