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A mixture of aluminium and zinc weighing 1.67 g was completely dissolved in acid and 1.69 litres of hydrogen measured at 0°C and 1 atmospheric pressure were evolved. What was the original weight of aluminium in the mixture?

Answer» <html><body><p></p>Solution :Both aluminium and zinc react with sulphuric acid to form hydrogen. Suppose, the mixture contains x g of aluminium. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, amount of zinc in the mixture = `1.67 -x g`. The corresponding equations are: <br/> `underset(53.96 g)(2Al) + H_(2)SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) to underset(3 xx 22.4 "L at S.T.P.")(Al_(2)(SO_(4))_(3)) + 3H_(2)` <br/> `underset(65.38 g)(Zn) + H_(2)SO_(4) to underset(22.4 L "at S.T.P")(ZnSO_(4)) + H_(2)` <br/> `therefore 53.96` g of Al evolve `H_(2) = 3 xx 22.4` L at S.T.P. <br/> `therefore x <a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>` of Al will evolve `H_(2) = (3 xx 22.4)/(53.96) xx x` <br/> `=1.24 x` L at S.T.P. <br/> <a href="https://interviewquestions.tuteehub.com/tag/similarly-1208242" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILARLY">SIMILARLY</a>, `therefore 1.24 x + (22.4)/(65.38) xx (1.67 -x) = 1.69` <br/> which gives `x = 1.24` <br/> Therefore, the <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of aluminium in the given sample is 1.24 g.</body></html>


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