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A mixture of C_(4)H_(8) and C_(2)H_(4) was completely burnt in excess of oxygen yielding equal volumes of CO_(2) and steam. Calculate the percentage (by volume ) of the compounds in the original mixture: |
Answer» <html><body><p>25% `C_(4)H_(8)` and 75% `C_(2)H_(4)` <br/><a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>% `C_(4)H_(8)` and 70% `C_(2)H_(4)` <br/>75% `C_(4)H_(8)` and25% `C_(2)H_(4)` <br/>50% `C_(4)H_(8)` and 50% `C_(2)H_(4)` </p>Answer :A::B::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |