1.

A mixture of CO and CO_2 is found to have a density of 1.5 g/L at 30^(@)C and 740 torr . What is the composition of the mixture .

Answer»

`CO = 0.3575 , CO_2 = 0.64225`
`CO = 0.64225 , CO_2 = 0.3575`
`CO = 0.500 , CO_(2) = 0.500`
`CO = 0.2500 , CO_(2) = 0.7500`

Solution :Useexpression , ` d = (PM)/(RT)`
`implies M = (DRT)/(P) = (1.5 xx 0.0821 xx 303 xx 76)/(74)`
`= 38.276`
Let one mole of the MIXTURE CONTAIN , N mole of CO and (1 -n) mole of `CO_(2)`
`n xx 28 + (1 - n) xx 44 = 1 xx 38.276`
[Molecular weights , `CO = 28 CO_(2) = 44]` since n= 0.35775
Number of moles `CO = 0.35775` & number of moles of `CO_(2) = 0.64225`


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