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A mixture of CO and CO_2 is found to have a density of 1.5 g/L at 30^(@)C and 740 torr . What is the composition of the mixture .

Answer» <html><body><p>`CO = 0.3575 , CO_2 = 0.64225`<br/>`CO = 0.64225 , CO_2 = 0.3575`<br/>`CO = 0.500 , CO_(2) = 0.500`<br/>`CO = 0.2500 , CO_(2) = 0.7500` <br/></p>Solution :Useexpression , ` d = (<a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a>)/(RT)` <br/> `implies M = (<a href="https://interviewquestions.tuteehub.com/tag/drt-433194" style="font-weight:bold;" target="_blank" title="Click to know more about DRT">DRT</a>)/(P) = (1.5 xx 0.0821 xx 303 xx 76)/(74)` <br/> `= 38.276` <br/> Let one mole of the <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> <a href="https://interviewquestions.tuteehub.com/tag/contain-409810" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAIN">CONTAIN</a> , <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> mole of CO and (1 -n) mole of `CO_(2)` <br/> `n xx 28 + (1 - n) xx 44 = 1 xx 38.276` <br/> [Molecular weights , `CO = 28 CO_(2) = 44]` since n= 0.35775 <br/> Number of moles `CO = 0.35775` &amp; number of moles of `CO_(2) = 0.64225`</body></html>


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